(i) f (x) is continuous and defined for all real numbers (ii) f '(-5) = 0 ,; ,f &#

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5. Continuity and Differentiation

normal

$(i)$ $f (x)$ is continuous and defined for all real numbers

$(ii)$ $f '(-5) = 0 \,; \,f '(2)$ is not defined and $f '(4) = 0$

$(iii)$ $(-5, 12)$ is a point which lies on the graph of $f (x)$

$(iv)$ $f ''(2)$ is undefined, but $f ''(x)$ is negative everywhere else.

$(v)$ the signs of $f '(x)$ is given below

Possible graph of $y = f (x)$ is

A

B

C

D

Solution

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Standard 12

Mathematics

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